What are the solutions to the equation 4(x+8)^2=28 ?

The solutions to the equation 4(x+8)^2=28 are x=sqrt(7)-8,x=-sqrt(7)-8

Find the zeros of 4(x+8)^2=28

The zeros of 4(x+8)^2=28 are x=sqrt(7)-8,x=-sqrt(7)-8

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4 (x + 8)^{2} = 28

x = 7 - 8, x = - 7 - 8

Decimal Notation

x = - 5.35424 \dots, x = - 10.64575 \dots

Solution steps

4 (x + 8)^{2} = 28

Divide both sides by

4

(x + 8)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 8 = 7 : x = 7 - 8

Solve

x + 8 = - 7 : x = - 7 - 8

The solutions to the quadratic equation are:

x = 7 - 8, x = - 7 - 8

x, (λ^{2} - 9) x^{2} + (λ^{2} - 16) y^{2} = λ

- 5 m^{2} - 5 m - 56 = 0

3 x + x^{2} = 0

(x - 5)^{2} = 32

2 x^{2} - 0.8 x - 0.1 = 0

What are the solutions to the equation 4(x+8)^2=28 ?
The solutions to the equation 4(x+8)^2=28 are x=sqrt(7)-8,x=-sqrt(7)-8
Find the zeros of 4(x+8)^2=28
The zeros of 4(x+8)^2=28 are x=sqrt(7)-8,x=-sqrt(7)-8