What are the solutions to the equation -λ^2-2λ-3=0 ?

The solutions to the equation -λ^2-2λ-3=0 are λ=-1-sqrt(2)i,λ=-1+sqrt(2)i

Find the zeros of -λ^2-2λ-3=0

The zeros of -λ^2-2λ-3=0 are λ=-1-sqrt(2)i,λ=-1+sqrt(2)i

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- λ^{2} - 2 λ - 3 = 0

λ = - 1 - 2 i, λ = - 1 + 2 i

Solution steps

- λ^{2} - 2 λ - 3 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 1 ) ( - 3 )}{2 ( - 1 )}

Simplify

(- 2)^{2} - 4 (- 1) (- 3) : 22 i

λ_{1, 2} = \frac{- ( - 2 ) \pm 2 2 i}{2 ( - 1 )}

Separate the solutions

λ_{1} = \frac{- ( - 2 ) + 2 2 i}{2 ( - 1 )}, λ_{2} = \frac{- ( - 2 ) - 2 2 i}{2 ( - 1 )}

λ = \frac{- ( - 2 ) + 2 2 i}{2 ( - 1 )} : - 1 - 2 i

λ = \frac{- ( - 2 ) - 2 2 i}{2 ( - 1 )} : - 1 + 2 i

The solutions to the quadratic equation are:

λ = - 1 - 2 i, λ = - 1 + 2 i

2 x^{2} = 1 - x

2 x^{2} = 120

2 x^{2} = 11 x

5 r^{2} - 8 r = 0

4 x^{2} + 8 x = 9

What are the solutions to the equation -λ^2-2λ-3=0 ?
The solutions to the equation -λ^2-2λ-3=0 are λ=-1-sqrt(2)i,λ=-1+sqrt(2)i
Find the zeros of -λ^2-2λ-3=0
The zeros of -λ^2-2λ-3=0 are λ=-1-sqrt(2)i,λ=-1+sqrt(2)i