What are the solutions to the equation 9x^2+6x+1=0 ?

The solutions to the equation 9x^2+6x+1=0 are x=-1/3

Find the zeros of 9x^2+6x+1=0

The zeros of 9x^2+6x+1=0 are x=-1/3

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9 x^{2} + 6 x + 1 = 0

x = - \frac{1}{3}

Decimal Notation

x = - 0.33333 \dots

Solution steps

9 x^{2} + 6 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 9 \cdot 1}{2 \cdot 9}

6^{2} - 4 \cdot 9 \cdot 1 = 0

x_{1, 2} = \frac{- 6 \pm 0}{2 \cdot 9}

x = \frac{- 6}{2 \cdot 9}

\frac{- 6}{2 \cdot 9} = - \frac{1}{3}

x = - \frac{1}{3}

The solution to the quadratic equation is:

x = - \frac{1}{3}

2 h - 8 = h + 17

4 - 4

\frac{48 x ^{3}}{3 x y ^{2}}

- \frac{1}{3} \cdot 9

3 x^{3} + 15 x^{2} + 2 x + 10

What are the solutions to the equation 9x^2+6x+1=0 ?
The solutions to the equation 9x^2+6x+1=0 are x=-1/3
Find the zeros of 9x^2+6x+1=0
The zeros of 9x^2+6x+1=0 are x=-1/3