What are the solutions to the equation 3x-x^2=-3x ?

The solutions to the equation 3x-x^2=-3x are x=0,x=6

Find the zeros of 3x-x^2=-3x

The zeros of 3x-x^2=-3x are x=0,x=6

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3 x - x^{2} = - 3 x

x = 0, x = 6

Solution steps

3 x - x^{2} = - 3 x

Move

3 x

to the left side

- x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

6^{2} - 4 (- 1) \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 ( - 1 )}, x_{2} = \frac{- 6 - 6}{2 ( - 1 )}

x = \frac{- 6 + 6}{2 ( - 1 )} : 0

x = \frac{- 6 - 6}{2 ( - 1 )} : 6

The solutions to the quadratic equation are:

x = 0, x = 6

\frac{x ^{2} - 1}{2} = \frac{4 x}{3}

x, 4 x^{2} = 9 x - 2

x^{2} + 40 = 14 x

x^{2} - (a + 2) x = - 2 a

2 x^{2} = 400

What are the solutions to the equation 3x-x^2=-3x ?
The solutions to the equation 3x-x^2=-3x are x=0,x=6
Find the zeros of 3x-x^2=-3x
The zeros of 3x-x^2=-3x are x=0,x=6