What are the solutions to the equation (x+2)^2+(x-2)^2=0 ?

The solutions to the equation (x+2)^2+(x-2)^2=0 are x=2i,x=-2i

Find the zeros of (x+2)^2+(x-2)^2=0

The zeros of (x+2)^2+(x-2)^2=0 are x=2i,x=-2i

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(x + 2)^{2} + (x - 2)^{2} = 0

x = 2 i, x = - 2 i

Solution steps

(x + 2)^{2} + (x - 2)^{2} = 0

Expand

(x + 2)^{2} + (x - 2)^{2} : 2 x^{2} + 8

2 x^{2} + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 2 \cdot 8}{2 \cdot 2}

Simplify

0^{2} - 4 \cdot 2 \cdot 8 : 8 i

x_{1, 2} = \frac{- 0 \pm 8 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 0 + 8 i}{2 \cdot 2}, x_{2} = \frac{- 0 - 8 i}{2 \cdot 2}

x = \frac{- 0 + 8 i}{2 \cdot 2} : 2 i

x = \frac{- 0 - 8 i}{2 \cdot 2} : - 2 i

The solutions to the quadratic equation are:

x = 2 i, x = - 2 i

4 x^{2} - 20 x + 25 = 16

2 x^{2} + 7 x = (10 x - 7) (2 x + 7)

y^{2} + 4 y - 8 = 0

x (- x) + (- 2 (3)) = - 14

12 z^{2} + z = 6

What are the solutions to the equation (x+2)^2+(x-2)^2=0 ?
The solutions to the equation (x+2)^2+(x-2)^2=0 are x=2i,x=-2i
Find the zeros of (x+2)^2+(x-2)^2=0
The zeros of (x+2)^2+(x-2)^2=0 are x=2i,x=-2i