What are the solutions to the equation 2x^2-10x+2=0 ?

The solutions to the equation 2x^2-10x+2=0 are x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2

Find the zeros of 2x^2-10x+2=0

The zeros of 2x^2-10x+2=0 are x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2

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2 x^{2} - 10 x + 2 = 0

x = \frac{5 + 21}{2}, x = \frac{5 - 21}{2}

Decimal Notation

x = 4.79128 \dots, x = 0.20871 \dots

Solution steps

2 x^{2} - 10 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 \cdot 2}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 \cdot 2 = 221

x_{1, 2} = \frac{- ( - 10 ) \pm 2 21}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 21}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 21}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 21}{2 \cdot 2} : \frac{5 + 21}{2}

x = \frac{- ( - 10 ) - 2 21}{2 \cdot 2} : \frac{5 - 21}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 21}{2}, x = \frac{5 - 21}{2}

x, x^{2} - 3 k x + 9 = 0

x, 3 x^{2} + 2 m x - 9 = 0

x, x^{2} + 3 x y + y^{2} = 1

5 x^{2} + 28 x - 2 = 7 x - 6

x^{2} + c = x

What are the solutions to the equation 2x^2-10x+2=0 ?
The solutions to the equation 2x^2-10x+2=0 are x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2
Find the zeros of 2x^2-10x+2=0
The zeros of 2x^2-10x+2=0 are x=(5+sqrt(21))/2 ,x=(5-sqrt(21))/2