What are the solutions to the equation (x-1)^2=3x-5 ?

The solutions to the equation (x-1)^2=3x-5 are x=3,x=2

Find the zeros of (x-1)^2=3x-5

The zeros of (x-1)^2=3x-5 are x=3,x=2

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(x - 1)^{2} = 3 x - 5

x = 3, x = 2

Solution steps

(x - 1)^{2} = 3 x - 5

Expand

(x - 1)^{2} : x^{2} - 2 x + 1

x^{2} - 2 x + 1 = 3 x - 5

Move

5

to the left side

x^{2} - 2 x + 6 = 3 x

Move

3 x

to the left side

x^{2} - 5 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 6}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 6 = 1

x_{1, 2} = \frac{- ( - 5 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 1}{2 \cdot 1}

x = \frac{- ( - 5 ) + 1}{2 \cdot 1} : 3

x = \frac{- ( - 5 ) - 1}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 3, x = 2

20.03 = 22.4 \cdot 1000 x (\frac{0.113 - x}{2})

\frac{3 ^{2}}{25} + \frac{y ^{2}}{16} = 1

2 (x + 3)^{2} = (x + 2) (x - 2)

9 h^{2} - 12 h + 4 = 0

x^{(2)} + 4 x + 4 = 1

What are the solutions to the equation (x-1)^2=3x-5 ?
The solutions to the equation (x-1)^2=3x-5 are x=3,x=2
Find the zeros of (x-1)^2=3x-5
The zeros of (x-1)^2=3x-5 are x=3,x=2