What are the solutions to the equation 2x^2-378.4x+17856=0 ?

The solutions to the equation 2x^2-378.4x+17856=0 are x= 496/5 ,x=90

Find the zeros of 2x^2-378.4x+17856=0

The zeros of 2x^2-378.4x+17856=0 are x= 496/5 ,x=90

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2 x^{2} - 378.4 x + 17856 = 0

x = \frac{496}{5}, x = 90

Decimal

x = 99.2, x = 90

Solution steps

2 x^{2} - 378.4 x + 17856 = 0

Multiply both sides by

10

20 x^{2} - 3784 x + 178560 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3784 ) \pm ( - 3784 ) ^{2} - 4 \cdot 20 \cdot 178560}{2 \cdot 20}

(- 3784)^{2} - 4 \cdot 20 \cdot 178560 = 184

x_{1, 2} = \frac{- ( - 3784 ) \pm 184}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- ( - 3784 ) + 184}{2 \cdot 20}, x_{2} = \frac{- ( - 3784 ) - 184}{2 \cdot 20}

x = \frac{- ( - 3784 ) + 184}{2 \cdot 20} : \frac{496}{5}

x = \frac{- ( - 3784 ) - 184}{2 \cdot 20} : 90

The solutions to the quadratic equation are:

x = \frac{496}{5}, x = 90

2 x^{2} - x + 6

(2 x + 3)^{2} = 1

9 x^{2} = 11 + 6 x

x, 2 x^{2} h = 1000

A (x) = (x - 5) (x + 7)

What are the solutions to the equation 2x^2-378.4x+17856=0 ?
The solutions to the equation 2x^2-378.4x+17856=0 are x= 496/5 ,x=90
Find the zeros of 2x^2-378.4x+17856=0
The zeros of 2x^2-378.4x+17856=0 are x= 496/5 ,x=90