What are the solutions to the equation -x^2-9x+18=0 ?

The solutions to the equation -x^2-9x+18=0 are x=-(9+3sqrt(17))/2 ,x=(3sqrt(17)-9)/2

Find the zeros of -x^2-9x+18=0

The zeros of -x^2-9x+18=0 are x=-(9+3sqrt(17))/2 ,x=(3sqrt(17)-9)/2

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- x^{2} - 9 x + 18 = 0

x = - \frac{9 + 3 17}{2}, x = \frac{3 17 - 9}{2}

Decimal Notation

x = - 10.68465 \dots, x = 1.68465 \dots

Solution steps

- x^{2} - 9 x + 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 1 ) \cdot 18}{2 ( - 1 )}

(- 9)^{2} - 4 (- 1) \cdot 18 = 317

x_{1, 2} = \frac{- ( - 9 ) \pm 3 17}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 3 17}{2 ( - 1 )}, x_{2} = \frac{- ( - 9 ) - 3 17}{2 ( - 1 )}

x = \frac{- ( - 9 ) + 3 17}{2 ( - 1 )} : - \frac{9 + 3 17}{2}

x = \frac{- ( - 9 ) - 3 17}{2 ( - 1 )} : \frac{3 17 - 9}{2}

The solutions to the quadratic equation are:

x = - \frac{9 + 3 17}{2}, x = \frac{3 17 - 9}{2}

x, x^{2} + 4 y^{2} + 4 y + 2 z^{2} - 2 z = 4

x, x^{2} + y^{2} + 136 = 4 (5 y - 3 x)

400 = 4 (x) \cdot x

x^{2} - 5 x + 8 = 2

- 5 x^{2} + 8 x - 2 = 0

What are the solutions to the equation -x^2-9x+18=0 ?
The solutions to the equation -x^2-9x+18=0 are x=-(9+3sqrt(17))/2 ,x=(3sqrt(17)-9)/2
Find the zeros of -x^2-9x+18=0
The zeros of -x^2-9x+18=0 are x=-(9+3sqrt(17))/2 ,x=(3sqrt(17)-9)/2