What are the solutions to the equation r^2+6r+279/4 =0 ?

The solutions to the equation r^2+6r+279/4 =0 are r=-3+i(9sqrt(3))/2 ,r=-3-i(9sqrt(3))/2

Find the zeros of r^2+6r+279/4 =0

The zeros of r^2+6r+279/4 =0 are r=-3+i(9sqrt(3))/2 ,r=-3-i(9sqrt(3))/2

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r^{2} + 6 r + \frac{279}{4} = 0

r = - 3 + i \frac{9 3}{2}, r = - 3 - i \frac{9 3}{2}

Solution steps

r^{2} + 6 r + \frac{279}{4} = 0

Multiply both sides by

4

4 r^{2} + 24 r + 279 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 279}{2 \cdot 4}

Simplify

2 4^{2} - 4 \cdot 4 \cdot 279 : 363 i

r_{1, 2} = \frac{- 24 \pm 36 3 i}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- 24 + 36 3 i}{2 \cdot 4}, r_{2} = \frac{- 24 - 36 3 i}{2 \cdot 4}

r = \frac{- 24 + 36 3 i}{2 \cdot 4} : - 3 + i \frac{9 3}{2}

r = \frac{- 24 - 36 3 i}{2 \cdot 4} : - 3 - i \frac{9 3}{2}

The solutions to the quadratic equation are:

r = - 3 + i \frac{9 3}{2}, r = - 3 - i \frac{9 3}{2}

(x - 3) (x + 18) = 0

\frac{x ^{2}}{8 + 3} = 19

12.5 x^{2} + 92.4 x - 4158 = 0

\frac{x ^{2}}{4} = 2 x - 3

l (t) = 2 + t^{2}

What are the solutions to the equation r^2+6r+279/4 =0 ?
The solutions to the equation r^2+6r+279/4 =0 are r=-3+i(9sqrt(3))/2 ,r=-3-i(9sqrt(3))/2
Find the zeros of r^2+6r+279/4 =0
The zeros of r^2+6r+279/4 =0 are r=-3+i(9sqrt(3))/2 ,r=-3-i(9sqrt(3))/2