What are the solutions to the equation 8x^2+10x=3 ?

The solutions to the equation 8x^2+10x=3 are x= 1/4 ,x=-3/2

Find the zeros of 8x^2+10x=3

The zeros of 8x^2+10x=3 are x= 1/4 ,x=-3/2

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8 x^{2} + 10 x = 3

x = \frac{1}{4}, x = - \frac{3}{2}

Decimal Notation

x = 0.25, x = - 1.5

Solution steps

8 x^{2} + 10 x = 3

Move

3

to the left side

8 x^{2} + 10 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 8 ( - 3 )}{2 \cdot 8}

1 0^{2} - 4 \cdot 8 (- 3) = 14

x_{1, 2} = \frac{- 10 \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 10 + 14}{2 \cdot 8}, x_{2} = \frac{- 10 - 14}{2 \cdot 8}

x = \frac{- 10 + 14}{2 \cdot 8} : \frac{1}{4}

x = \frac{- 10 - 14}{2 \cdot 8} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{1}{4}, x = - \frac{3}{2}

x^{2} + 4 x - 1 = 7

c^{1} + c^{2} = - 2

x, x^{2} + k x + 36 = 0

(x + 1)^{2} - 8 \cdot (x + 1) + 7 = 0

x, x^{2} + (y - 32 x)^{2} = 1

What are the solutions to the equation 8x^2+10x=3 ?
The solutions to the equation 8x^2+10x=3 are x= 1/4 ,x=-3/2
Find the zeros of 8x^2+10x=3
The zeros of 8x^2+10x=3 are x= 1/4 ,x=-3/2