What are the solutions to the equation -0.01x^2-0.2x+8=0 ?

The solutions to the equation -0.01x^2-0.2x+8=0 are x=-40,x=20

Find the zeros of -0.01x^2-0.2x+8=0

The zeros of -0.01x^2-0.2x+8=0 are x=-40,x=20

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- 0.01 x^{2} - 0.2 x + 8 = 0

x = - 40, x = 20

Solution steps

- 0.01 x^{2} - 0.2 x + 8 = 0

Multiply both sides by

100

- x^{2} - 20 x + 800 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 ( - 1 ) \cdot 800}{2 ( - 1 )}

(- 20)^{2} - 4 (- 1) \cdot 800 = 60

x_{1, 2} = \frac{- ( - 20 ) \pm 60}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 60}{2 ( - 1 )}, x_{2} = \frac{- ( - 20 ) - 60}{2 ( - 1 )}

x = \frac{- ( - 20 ) + 60}{2 ( - 1 )} : - 40

x = \frac{- ( - 20 ) - 60}{2 ( - 1 )} : 20

The solutions to the quadratic equation are:

x = - 40, x = 20

x, y = - 0.00001 x^{2} + 0.01 x + 0.2001

2 m^{2} - 13 m - 45 = 0

3 a^{2} + 9 a - 30 = 0

x, 5 x^{2} + 3 = 2 y^{3} + 5

x^{2} + 5 x - 22 = 8 x + 32

What are the solutions to the equation -0.01x^2-0.2x+8=0 ?
The solutions to the equation -0.01x^2-0.2x+8=0 are x=-40,x=20
Find the zeros of -0.01x^2-0.2x+8=0
The zeros of -0.01x^2-0.2x+8=0 are x=-40,x=20