What are the solutions to the equation 0=x^2+5x+2 ?

The solutions to the equation 0=x^2+5x+2 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2

Find the zeros of 0=x^2+5x+2

The zeros of 0=x^2+5x+2 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2

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0 = x^{2} + 5 x + 2

x = \frac{- 5 + 17}{2}, x = \frac{- 5 - 17}{2}

Decimal Notation

x = - 0.43844 \dots, x = - 4.56155 \dots

Solution steps

0 = x^{2} + 5 x + 2

Switch sides

x^{2} + 5 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 2 = 17

x_{1, 2} = \frac{- 5 \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 17}{2 \cdot 1}, x_{2} = \frac{- 5 - 17}{2 \cdot 1}

x = \frac{- 5 + 17}{2 \cdot 1} : \frac{- 5 + 17}{2}

x = \frac{- 5 - 17}{2 \cdot 1} : \frac{- 5 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{- 5 + 17}{2}, x = \frac{- 5 - 17}{2}

30625000 - 336875 x + 612.5 x^{2} = 0

2 m^{2} - 6 m - 8 = 0

x, \frac{x ^{2}}{q} + \frac{y ^{2}}{4} = 1

x, f = 2 x^{2} - 2 x + 1

2 (x - 2)^{2} - (3 x - 6) = 9

What are the solutions to the equation 0=x^2+5x+2 ?
The solutions to the equation 0=x^2+5x+2 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2
Find the zeros of 0=x^2+5x+2
The zeros of 0=x^2+5x+2 are x=(-5+sqrt(17))/2 ,x=(-5-sqrt(17))/2