What are the solutions to the equation x^2+1.6x=0.36 ?

The solutions to the equation x^2+1.6x=0.36 are x= 1/5 ,x=-9/5

Find the zeros of x^2+1.6x=0.36

The zeros of x^2+1.6x=0.36 are x= 1/5 ,x=-9/5

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x^{2} + 1.6 x = 0.36

x = \frac{1}{5}, x = - \frac{9}{5}

Decimal Notation

x = 0.2, x = - 1.8

Solution steps

x^{2} + 1.6 x = 0.36

Multiply both sides by

100

100 x^{2} + 160 x = 36

Move

36

to the left side

100 x^{2} + 160 x - 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 160 \pm 16 0 ^{2} - 4 \cdot 100 ( - 36 )}{2 \cdot 100}

16 0^{2} - 4 \cdot 100 (- 36) = 200

x_{1, 2} = \frac{- 160 \pm 200}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 160 + 200}{2 \cdot 100}, x_{2} = \frac{- 160 - 200}{2 \cdot 100}

x = \frac{- 160 + 200}{2 \cdot 100} : \frac{1}{5}

x = \frac{- 160 - 200}{2 \cdot 100} : - \frac{9}{5}

The solutions to the quadratic equation are:

x = \frac{1}{5}, x = - \frac{9}{5}

(x - 4) \cdot (x + 2) = 0

x (2 x - 1) = 1

7 x - x^{2} - 6 = 0

1 9^{2} + 1 6^{2} = x^{2}

3 x^{2} - 3 x - 6 = 0

What are the solutions to the equation x^2+1.6x=0.36 ?
The solutions to the equation x^2+1.6x=0.36 are x= 1/5 ,x=-9/5
Find the zeros of x^2+1.6x=0.36
The zeros of x^2+1.6x=0.36 are x= 1/5 ,x=-9/5