What are the solutions to the equation 7s^2+9s-4=0 ?

The solutions to the equation 7s^2+9s-4=0 are s=(-9+sqrt(193))/(14),s=(-9-sqrt(193))/(14)

Find the zeros of 7s^2+9s-4=0

The zeros of 7s^2+9s-4=0 are s=(-9+sqrt(193))/(14),s=(-9-sqrt(193))/(14)

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7 s^{2} + 9 s - 4 = 0

s = \frac{- 9 + 193}{14}, s = \frac{- 9 - 193}{14}

Decimal Notation

s = 0.34946 \dots, s = - 1.63517 \dots

Solution steps

7 s^{2} + 9 s - 4 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 7 ( - 4 )}{2 \cdot 7}

9^{2} - 4 \cdot 7 (- 4) = 193

s_{1, 2} = \frac{- 9 \pm 193}{2 \cdot 7}

Separate the solutions

s_{1} = \frac{- 9 + 193}{2 \cdot 7}, s_{2} = \frac{- 9 - 193}{2 \cdot 7}

s = \frac{- 9 + 193}{2 \cdot 7} : \frac{- 9 + 193}{14}

s = \frac{- 9 - 193}{2 \cdot 7} : \frac{- 9 - 193}{14}

The solutions to the quadratic equation are:

s = \frac{- 9 + 193}{14}, s = \frac{- 9 - 193}{14}

x^{2} + 25 = 10 x + 4

2 y^{2} = - y + 6

x, (x + 5) (x + 2) = (x + 2)

v, v + 3 \cdot 1 0^{- 3} (v - 1)^{2} 10 \cdot 1 0^{3} = 5

(3 x - 4) (3 x - 4) = 8^{8}

What are the solutions to the equation 7s^2+9s-4=0 ?
The solutions to the equation 7s^2+9s-4=0 are s=(-9+sqrt(193))/(14),s=(-9-sqrt(193))/(14)
Find the zeros of 7s^2+9s-4=0
The zeros of 7s^2+9s-4=0 are s=(-9+sqrt(193))/(14),s=(-9-sqrt(193))/(14)