What are the solutions to the equation -2x^2=-512 ?

The solutions to the equation -2x^2=-512 are x=16,x=-16

Find the zeros of -2x^2=-512

The zeros of -2x^2=-512 are x=16,x=-16

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- 2 x^{2} = - 512

x = 16, x = - 16

Solution steps

- 2 x^{2} = - 512

Divide both sides by

- 2

x^{2} = 256

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 256, x = - 256

256 = 16

- 256 = - 16

x = 16, x = - 16

4 n^{2} + 5 n = 6

(1 - x) (6 - x) + 4 = 0

x (12 - x) = 3 (4 x - 3)

3 x^{2} + 11 x + 3 = 0

A = (2 x - 5)^{2} - 3 (2 x - 5) (x - 4)

What are the solutions to the equation -2x^2=-512 ?
The solutions to the equation -2x^2=-512 are x=16,x=-16
Find the zeros of -2x^2=-512
The zeros of -2x^2=-512 are x=16,x=-16