What are the solutions to the equation 0=x^2+10x ?

The solutions to the equation 0=x^2+10x are x=0,x=-10

Find the zeros of 0=x^2+10x

The zeros of 0=x^2+10x are x=0,x=-10

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0 = x^{2} + 10 x

x = 0, x = - 10

Solution steps

0 = x^{2} + 10 x

Switch sides

x^{2} + 10 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 0 = 10

x_{1, 2} = \frac{- 10 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 10}{2 \cdot 1}, x_{2} = \frac{- 10 - 10}{2 \cdot 1}

x = \frac{- 10 + 10}{2 \cdot 1} : 0

x = \frac{- 10 - 10}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = 0, x = - 10

x^{2} + (\frac{48}{7})^{2} = 1

x, 3 x^{2} - 2 x y + 3 y^{2} - 4 x - 4 y - 12 = 0

x^{2} - 4 x - 160 = 0

x, 7 x^{2} + 2 y^{2} + 2 x - 7 y + 16 = 0

266 = 0.68 \cdot 100 \cdot X \cdot 1.79 \cdot (7.2 - 0.4 \cdot X)

What are the solutions to the equation 0=x^2+10x ?
The solutions to the equation 0=x^2+10x are x=0,x=-10
Find the zeros of 0=x^2+10x
The zeros of 0=x^2+10x are x=0,x=-10