What are the solutions to the equation 0.1x^2+0.4x-0.3=0 ?

The solutions to the equation 0.1x^2+0.4x-0.3=0 are x=-2+sqrt(7),x=-2-sqrt(7)

Find the zeros of 0.1x^2+0.4x-0.3=0

The zeros of 0.1x^2+0.4x-0.3=0 are x=-2+sqrt(7),x=-2-sqrt(7)

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0.1 x^{2} + 0.4 x - 0.3 = 0

x = - 2 + 7, x = - 2 - 7

Decimal Notation

x = 0.64575 \dots, x = - 4.64575 \dots

Solution steps

0.1 x^{2} + 0.4 x - 0.3 = 0

Multiply both sides by

10

x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 3) = 27

x_{1, 2} = \frac{- 4 \pm 2 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 7}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 7}{2 \cdot 1}

x = \frac{- 4 + 2 7}{2 \cdot 1} : - 2 + 7

x = \frac{- 4 - 2 7}{2 \cdot 1} : - 2 - 7

The solutions to the quadratic equation are:

x = - 2 + 7, x = - 2 - 7

4 x^{2} + 4 (2 x + 1) = 0

- x^{2} - 56 = 0

0 = - 3 x^{2} + 2 x + 1

- 2.1 y^{2} + 8.04 y = 7.4

A, A^{2} + 2 A B + B^{2} = 100

What are the solutions to the equation 0.1x^2+0.4x-0.3=0 ?
The solutions to the equation 0.1x^2+0.4x-0.3=0 are x=-2+sqrt(7),x=-2-sqrt(7)
Find the zeros of 0.1x^2+0.4x-0.3=0
The zeros of 0.1x^2+0.4x-0.3=0 are x=-2+sqrt(7),x=-2-sqrt(7)