What are the solutions to the equation (u-2)(u-8)=0 ?

The solutions to the equation (u-2)(u-8)=0 are u=2,u=8

Find the zeros of (u-2)(u-8)=0

The zeros of (u-2)(u-8)=0 are u=2,u=8

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(u - 2) (u - 8) = 0

u = 2, u = 8

Solution steps

(u - 2) (u - 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

u - 2 = 0 or u - 8 = 0

Solve

u - 2 = 0 : u = 2

Solve

u - 8 = 0 : u = 8

The solutions to the quadratic equation are:

u = 2, u = 8

x, x^{2} + x y - 10 = 0

- 6 x^{2} + 120 x = 0

6 x^{2} + (10 a - 2) x - 4 a + 12 = 0

72 x^{2} + 30 x - 24 = 0

x^{2} - 17 x + 6 = 0

What are the solutions to the equation (u-2)(u-8)=0 ?
The solutions to the equation (u-2)(u-8)=0 are u=2,u=8
Find the zeros of (u-2)(u-8)=0
The zeros of (u-2)(u-8)=0 are u=2,u=8