What are the solutions to the equation a^2-28a-480=0 ?

The solutions to the equation a^2-28a-480=0 are a=40,a=-12

Find the zeros of a^2-28a-480=0

The zeros of a^2-28a-480=0 are a=40,a=-12

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a^{2} - 28 a - 480 = 0

a = 40, a = - 12

Solution steps

a^{2} - 28 a - 480 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 28 ) \pm ( - 28 ) ^{2} - 4 \cdot 1 \cdot ( - 480 )}{2 \cdot 1}

(- 28)^{2} - 4 \cdot 1 \cdot (- 480) = 52

a_{1, 2} = \frac{- ( - 28 ) \pm 52}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 28 ) + 52}{2 \cdot 1}, a_{2} = \frac{- ( - 28 ) - 52}{2 \cdot 1}

a = \frac{- ( - 28 ) + 52}{2 \cdot 1} : 40

a = \frac{- ( - 28 ) - 52}{2 \cdot 1} : - 12

The solutions to the quadratic equation are:

a = 40, a = - 12

\frac{2}{3} x^{2} - 16 = 32

x, x^{2} + y^{2} - 6 x + 10 y + 34 = 0

3 x^{2} + 4 x = 4

6 x^{2} - 12 x = - 1

1 4^{2} + x^{2} = 1 7^{2}

What are the solutions to the equation a^2-28a-480=0 ?
The solutions to the equation a^2-28a-480=0 are a=40,a=-12
Find the zeros of a^2-28a-480=0
The zeros of a^2-28a-480=0 are a=40,a=-12