What are the solutions to the equation solvefor y,x=9-y^2 ?

The solutions to the equation solvefor y,x=9-y^2 are y=sqrt(-x+9),y=-sqrt(-x+9)

Find the zeros of solvefor y,x=9-y^2

The zeros of solvefor y,x=9-y^2 are y=sqrt(-x+9),y=-sqrt(-x+9)

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solve for

y, x = 9 - y^{2}

y = - x + 9, y = - - x + 9

Solution steps

x = 9 - y^{2}

Switch sides

9 - y^{2} = x

Move

9

to the right side

- y^{2} = x - 9

Divide both sides by

- 1

y^{2} = - x + 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - x + 9, y = - - x + 9

t, h = - 16 t^{2} + 50

12 x^{2} + 12 = 25 x

n (t) = - 2.82 t^{2} + 25.74 t + 60.87

(x - 6) (x - 8) = 7 (x - 1) (x + 8) + x^{2}

x, 2 x^{2} + 3 y^{2} + z^{2} - 12 x + 12 y + 2 z + 28 = 0

What are the solutions to the equation solvefor y,x=9-y^2 ?
The solutions to the equation solvefor y,x=9-y^2 are y=sqrt(-x+9),y=-sqrt(-x+9)
Find the zeros of solvefor y,x=9-y^2
The zeros of solvefor y,x=9-y^2 are y=sqrt(-x+9),y=-sqrt(-x+9)