What are the solutions to the equation (m-4)^2=7 ?

The solutions to the equation (m-4)^2=7 are m=sqrt(7)+4,m=-sqrt(7)+4

Find the zeros of (m-4)^2=7

The zeros of (m-4)^2=7 are m=sqrt(7)+4,m=-sqrt(7)+4

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(m - 4)^{2} = 7

m = 7 + 4, m = - 7 + 4

Decimal Notation

m = 6.64575 \dots, m = 1.35424 \dots

Solution steps

(m - 4)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

m - 4 = 7 : m = 7 + 4

Solve

m - 4 = - 7 : m = - 7 + 4

The solutions to the quadratic equation are:

m = 7 + 4, m = - 7 + 4

(\frac{23 + 2 y}{5})^{2} - (23 + 2 y) y + y^{2} = 1

5 x^{2} + 8 x - 14 = 0

(m - 4)^{2} = 9

2 (x + 3)^{2} + 12 = 4

2 x^{2} - 7 x + 4 = 9

What are the solutions to the equation (m-4)^2=7 ?
The solutions to the equation (m-4)^2=7 are m=sqrt(7)+4,m=-sqrt(7)+4
Find the zeros of (m-4)^2=7
The zeros of (m-4)^2=7 are m=sqrt(7)+4,m=-sqrt(7)+4