What are the solutions to the equation -6x^2+2=0 ?

The solutions to the equation -6x^2+2=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

Find the zeros of -6x^2+2=0

The zeros of -6x^2+2=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

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- 6 x^{2} + 2 = 0

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

- 6 x^{2} + 2 = 0

Move

2

to the right side

- 6 x^{2} = - 2

Divide both sides by

- 6

x^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{3}, x = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

3 x^{2} + x - 102 = 0

1 - x^{2}

x^{2} - 2 x + 50

x^{2} - 2 x + 13

2 x^{2} - x - 78 = 0

What are the solutions to the equation -6x^2+2=0 ?
The solutions to the equation -6x^2+2=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))
Find the zeros of -6x^2+2=0
The zeros of -6x^2+2=0 are x= 1/(sqrt(3)),x=-1/(sqrt(3))