What are the solutions to the equation (s^2-4)=0 ?

The solutions to the equation (s^2-4)=0 are s=2,s=-2

Find the zeros of (s^2-4)=0

The zeros of (s^2-4)=0 are s=2,s=-2

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(s^{2} - 4) = 0

s = 2, s = - 2

Solution steps

(s^{2} - 4) = 0

s^{2} - 4 = 0

Move

4

to the right side

s^{2} = 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

s = 4, s = - 4

4 = 2

- 4 = - 2

s = 2, s = - 2

(x - 1) (x + 4) + 4 = 0

\frac{49 + 25 - 9}{2 \cdot 7 \cdot 5} = \frac{49 + 49 - x ^{2}}{2 \cdot 7 \cdot 7}

x^{2} - 6 x - 4 = 0

e^{2} = 5

x, 0 = x^{2} + 5 x + 8

What are the solutions to the equation (s^2-4)=0 ?
The solutions to the equation (s^2-4)=0 are s=2,s=-2
Find the zeros of (s^2-4)=0
The zeros of (s^2-4)=0 are s=2,s=-2