What are the solutions to the equation n^2+9n+20=0 ?

The solutions to the equation n^2+9n+20=0 are n=-4,n=-5

Find the zeros of n^2+9n+20=0

The zeros of n^2+9n+20=0 are n=-4,n=-5

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n^{2} + 9 n + 20 = 0

n = - 4, n = - 5

Solution steps

n^{2} + 9 n + 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

n_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 9 + 1}{2 \cdot 1}, n_{2} = \frac{- 9 - 1}{2 \cdot 1}

n = \frac{- 9 + 1}{2 \cdot 1} : - 4

n = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

n = - 4, n = - 5

e^{- 5}

w^{2} - 17 w + 72

\frac{3 x}{4} - \frac{1}{3} = 1 - \frac{2}{3} (x - \frac{1}{6})

4 \geq 1 - 3 x \geq 2

\frac{1}{6} + \frac{5}{8}

What are the solutions to the equation n^2+9n+20=0 ?
The solutions to the equation n^2+9n+20=0 are n=-4,n=-5
Find the zeros of n^2+9n+20=0
The zeros of n^2+9n+20=0 are n=-4,n=-5