What are the solutions to the equation 2X^2-2X+1=0 ?

The solutions to the equation 2X^2-2X+1=0 are X= 1/2+i 1/2 ,X= 1/2-i 1/2

Find the zeros of 2X^2-2X+1=0

The zeros of 2X^2-2X+1=0 are X= 1/2+i 1/2 ,X= 1/2-i 1/2

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2 X^{2} - 2 X + 1 = 0

X = \frac{1}{2} + i \frac{1}{2}, X = \frac{1}{2} - i \frac{1}{2}

Solution steps

2 X^{2} - 2 X + 1 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

(- 2)^{2} - 4 \cdot 2 \cdot 1 : 2 i

X_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 2}

Separate the solutions

X_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 2}, X_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 2}

X = \frac{- ( - 2 ) + 2 i}{2 \cdot 2} : \frac{1}{2} + i \frac{1}{2}

X = \frac{- ( - 2 ) - 2 i}{2 \cdot 2} : \frac{1}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

X = \frac{1}{2} + i \frac{1}{2}, X = \frac{1}{2} - i \frac{1}{2}

P, P^{2} - P (\frac{1}{l} + 2 l) + 2 = 0

6 x^{2} + 480 = 0

x^{2} - 15 x + 12 = 0

x, x^{2} + 14 x + 49 = 0

n^{2} + 8 n = - 15

What are the solutions to the equation 2X^2-2X+1=0 ?
The solutions to the equation 2X^2-2X+1=0 are X= 1/2+i 1/2 ,X= 1/2-i 1/2
Find the zeros of 2X^2-2X+1=0
The zeros of 2X^2-2X+1=0 are X= 1/2+i 1/2 ,X= 1/2-i 1/2