What are the solutions to the equation 1/7 y^2= 3/7 y ?

The solutions to the equation 1/7 y^2= 3/7 y are y=3,y=0

Find the zeros of 1/7 y^2= 3/7 y

The zeros of 1/7 y^2= 3/7 y are y=3,y=0

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\frac{1}{7} y^{2} = \frac{3}{7} y

y = 3, y = 0

Solution steps

\frac{1}{7} y^{2} = \frac{3}{7} y

Multiply both sides by

7

y^{2} = 3 y

Move

3 y

to the left side

y^{2} - 3 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 0 = 3

y_{1, 2} = \frac{- ( - 3 ) \pm 3}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- ( - 3 ) + 3}{2 \cdot 1}, y_{2} = \frac{- ( - 3 ) - 3}{2 \cdot 1}

y = \frac{- ( - 3 ) + 3}{2 \cdot 1} : 3

y = \frac{- ( - 3 ) - 3}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

y = 3, y = 0

- x = x - x^{2}

2 - 2 k^{2} = 0

x = x (3 - x)

x = a (1 - \frac{z ^{2}}{b ^{2}}), z

x^{2} + 16 x = 41

What are the solutions to the equation 1/7 y^2= 3/7 y ?
The solutions to the equation 1/7 y^2= 3/7 y are y=3,y=0
Find the zeros of 1/7 y^2= 3/7 y
The zeros of 1/7 y^2= 3/7 y are y=3,y=0