What are the solutions to the equation 450x-5x^2=0 ?

The solutions to the equation 450x-5x^2=0 are x=0,x=90

Find the zeros of 450x-5x^2=0

The zeros of 450x-5x^2=0 are x=0,x=90

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450 x - 5 x^{2} = 0

x = 0, x = 90

Solution steps

450 x - 5 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 5 x^{2} + 450 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 450 \pm 45 0 ^{2} - 4 ( - 5 ) \cdot 0}{2 ( - 5 )}

45 0^{2} - 4 (- 5) \cdot 0 = 450

x_{1, 2} = \frac{- 450 \pm 450}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 450 + 450}{2 ( - 5 )}, x_{2} = \frac{- 450 - 450}{2 ( - 5 )}

x = \frac{- 450 + 450}{2 ( - 5 )} : 0

x = \frac{- 450 - 450}{2 ( - 5 )} : 90

The solutions to the quadratic equation are:

x = 0, x = 90

3 x^{2} - 8 x - 30 = 0

x, z = x^{2} y^{2}

(x + 1)^{2} + x^{2} = 25

\frac{x ^{2}}{6} - \frac{5 x}{12} - \frac{1}{4} = 0

3000 (1 + r)^{2} + 2000 (1 + r) = 5895.25

What are the solutions to the equation 450x-5x^2=0 ?
The solutions to the equation 450x-5x^2=0 are x=0,x=90
Find the zeros of 450x-5x^2=0
The zeros of 450x-5x^2=0 are x=0,x=90