What are the solutions to the equation z^2+z=2 ?

The solutions to the equation z^2+z=2 are z=1,z=-2

Find the zeros of z^2+z=2

The zeros of z^2+z=2 are z=1,z=-2

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z^{2} + z = 2

z = 1, z = - 2

Solution steps

z^{2} + z = 2

Move

2

to the left side

z^{2} + z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

z_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 3}{2 \cdot 1}, z_{2} = \frac{- 1 - 3}{2 \cdot 1}

z = \frac{- 1 + 3}{2 \cdot 1} : 1

z = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

z = 1, z = - 2

z^{2} + z = 1

4 (x + 12)^{2} = 28

x, 6 x^{2} + 2 y^{2} - 4 = 2 x^{2} y + 3 y

4 x^{2} + 7 x + 10 = 0

x, z = x^{2} + y^{2} - 1

What are the solutions to the equation z^2+z=2 ?
The solutions to the equation z^2+z=2 are z=1,z=-2
Find the zeros of z^2+z=2
The zeros of z^2+z=2 are z=1,z=-2