What are the solutions to the equation 64+b^2=289 ?

The solutions to the equation 64+b^2=289 are b=15,b=-15

Find the zeros of 64+b^2=289

The zeros of 64+b^2=289 are b=15,b=-15

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64 + b^{2} = 289

b = 15, b = - 15

Solution steps

64 + b^{2} = 289

Move

64

to the right side

b^{2} = 225

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

b = 225, b = - 225

225 = 15

- 225 = - 15

b = 15, b = - 15

x^{2} = 72 + 363

y, y^{2} - 4 y + 4 = X - 7

40 = 2 t + 2 t^{2}

x^{2} - 7 x - \frac{3}{4} = 0

n^{2} + n - 12 = 0

What are the solutions to the equation 64+b^2=289 ?
The solutions to the equation 64+b^2=289 are b=15,b=-15
Find the zeros of 64+b^2=289
The zeros of 64+b^2=289 are b=15,b=-15