What are the solutions to the equation m^2+18m+81=0 ?

The solutions to the equation m^2+18m+81=0 are m=-9

Find the zeros of m^2+18m+81=0

The zeros of m^2+18m+81=0 are m=-9

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m^{2} + 18 m + 81 = 0

m = - 9

Solution steps

m^{2} + 18 m + 81 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 81 = 0

m_{1, 2} = \frac{- 18 \pm 0}{2 \cdot 1}

m = \frac{- 18}{2 \cdot 1}

\frac{- 18}{2 \cdot 1} = - 9

m = - 9

The solution to the quadratic equation is:

m = - 9

9 = 10 x - x^{2}

4 = x^{2} - 2 x - 3

100 x^{2} - 140 x = - 28

- 5 x^{2} + 2 x + 11 = 0

2 x^{2} - 2 x + 15 = 0

What are the solutions to the equation m^2+18m+81=0 ?
The solutions to the equation m^2+18m+81=0 are m=-9
Find the zeros of m^2+18m+81=0
The zeros of m^2+18m+81=0 are m=-9