What are the solutions to the equation (t+1)^2=-9 ?

The solutions to the equation (t+1)^2=-9 are t=3i-1,t=-3i-1

Find the zeros of (t+1)^2=-9

The zeros of (t+1)^2=-9 are t=3i-1,t=-3i-1

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(t + 1)^{2} = - 9

t = 3 i - 1, t = - 3 i - 1

Solution steps

(t + 1)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

t + 1 = - 9 : t = 3 i - 1

Solve

t + 1 = - - 9 : t = - 3 i - 1

The solutions to the quadratic equation are:

t = 3 i - 1, t = - 3 i - 1

y^{2} - 5 y

10 x^{2} - 11 x + 1 = 0

3 x^{2} = 8 x + 1

x^{2} = 4 x - x^{2}

- 4 x^{2} + 4 x + 4 = 0

What are the solutions to the equation (t+1)^2=-9 ?
The solutions to the equation (t+1)^2=-9 are t=3i-1,t=-3i-1
Find the zeros of (t+1)^2=-9
The zeros of (t+1)^2=-9 are t=3i-1,t=-3i-1