What are the solutions to the equation (2-x)^2=-1 ?

The solutions to the equation (2-x)^2=-1 are x=-i+2,x=i+2

Find the zeros of (2-x)^2=-1

The zeros of (2-x)^2=-1 are x=-i+2,x=i+2

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(2 - x)^{2} = - 1

x = - i + 2, x = i + 2

Solution steps

(2 - x)^{2} = - 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 - x = - 1 : x = - i + 2

Solve

2 - x = - - 1 : x = i + 2

The solutions to the quadratic equation are:

x = - i + 2, x = i + 2

2 (3 x - 1) - 5 (1 - x) = x^{2} - 7

a = a^{2} 3

- 9 x^{2} + 6 x + 1 = 0

4 x^{2} + 5 x + 4 = 0

k^{2} - 18 k + 8 = - 9

What are the solutions to the equation (2-x)^2=-1 ?
The solutions to the equation (2-x)^2=-1 are x=-i+2,x=i+2
Find the zeros of (2-x)^2=-1
The zeros of (2-x)^2=-1 are x=-i+2,x=i+2