What are the solutions to the equation 2x^2-10x-8=0 ?

The solutions to the equation 2x^2-10x-8=0 are x=(5+sqrt(41))/2 ,x=(5-sqrt(41))/2

Find the zeros of 2x^2-10x-8=0

The zeros of 2x^2-10x-8=0 are x=(5+sqrt(41))/2 ,x=(5-sqrt(41))/2

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2 x^{2} - 10 x - 8 = 0

x = \frac{5 + 41}{2}, x = \frac{5 - 41}{2}

Decimal Notation

x = 5.70156 \dots, x = - 0.70156 \dots

Solution steps

2 x^{2} - 10 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 2 ( - 8 )}{2 \cdot 2}

(- 10)^{2} - 4 \cdot 2 (- 8) = 241

x_{1, 2} = \frac{- ( - 10 ) \pm 2 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 2 41}{2 \cdot 2}, x_{2} = \frac{- ( - 10 ) - 2 41}{2 \cdot 2}

x = \frac{- ( - 10 ) + 2 41}{2 \cdot 2} : \frac{5 + 41}{2}

x = \frac{- ( - 10 ) - 2 41}{2 \cdot 2} : \frac{5 - 41}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 41}{2}, x = \frac{5 - 41}{2}

3 x^{2} + 5 x = x^{2}

11 + 0.1 x - 0.0001 x^{2} = 35

n^{2} + 14 n + 48 = 0

3 x^{2} + 12 x + 3

0 = - 3010 + 497 x - \frac{93}{5} x^{2}

What are the solutions to the equation 2x^2-10x-8=0 ?
The solutions to the equation 2x^2-10x-8=0 are x=(5+sqrt(41))/2 ,x=(5-sqrt(41))/2
Find the zeros of 2x^2-10x-8=0
The zeros of 2x^2-10x-8=0 are x=(5+sqrt(41))/2 ,x=(5-sqrt(41))/2