What are the solutions to the equation 4.9x^2-36.75x+62=0 ?

The solutions to the equation 4.9x^2-36.75x+62=0 are x=(105+sqrt(1105))/(28),x=(105-sqrt(1105))/(28)

Find the zeros of 4.9x^2-36.75x+62=0

The zeros of 4.9x^2-36.75x+62=0 are x=(105+sqrt(1105))/(28),x=(105-sqrt(1105))/(28)

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4.9 x^{2} - 36.75 x + 62 = 0

x = \frac{105 + 1105}{28}, x = \frac{105 - 1105}{28}

Decimal Notation

x = 4.93719 \dots, x = 2.56280 \dots

Solution steps

4.9 x^{2} - 36.75 x + 62 = 0

Multiply both sides by

100

490 x^{2} - 3675 x + 6200 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3675 ) \pm ( - 3675 ) ^{2} - 4 \cdot 490 \cdot 6200}{2 \cdot 490}

(- 3675)^{2} - 4 \cdot 490 \cdot 6200 = 351105

x_{1, 2} = \frac{- ( - 3675 ) \pm 35 1105}{2 \cdot 490}

Separate the solutions

x_{1} = \frac{- ( - 3675 ) + 35 1105}{2 \cdot 490}, x_{2} = \frac{- ( - 3675 ) - 35 1105}{2 \cdot 490}

x = \frac{- ( - 3675 ) + 35 1105}{2 \cdot 490} : \frac{105 + 1105}{28}

x = \frac{- ( - 3675 ) - 35 1105}{2 \cdot 490} : \frac{105 - 1105}{28}

The solutions to the quadratic equation are:

x = \frac{105 + 1105}{28}, x = \frac{105 - 1105}{28}

(5 + y) 2 + (1 - 5 y) 2 = (5 y) 2 + y^{2} + y

- x^{2} - 4 x + 28 = 0

r^{2} - 3 r - 2 = 0

- 2 x^{2} + 2 x + 6 = 0

- 2 x^{2} + 10 x + 48 = 0

What are the solutions to the equation 4.9x^2-36.75x+62=0 ?
The solutions to the equation 4.9x^2-36.75x+62=0 are x=(105+sqrt(1105))/(28),x=(105-sqrt(1105))/(28)
Find the zeros of 4.9x^2-36.75x+62=0
The zeros of 4.9x^2-36.75x+62=0 are x=(105+sqrt(1105))/(28),x=(105-sqrt(1105))/(28)