What is factor n^2-22n+40 ?

The solution to factor n^2-22n+40 is (n-2)(n-20)

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factor n^2-22n+40

factor

n^{2} - 22 n + 40

(n - 2) (n - 20)

Solution steps

n^{2} - 22 n + 40

Break the expression into groups

= (n^{2} - 2 n) + (- 20 n + 40)

Factor out

n

from

n^{2} - 2 n : n (n - 2)

Factor out

- 20

from

- 20 n + 40 : - 20 (n - 2)

= n (n - 2) - 20 (n - 2)

Factor out common term

n - 2

= (n - 2) (n - 20)

(3 + 2 i) + (5 - 3 i)

(a^{2} - b^{2} - c^{2}) - 4 b^{2} c^{2}

p^{2} + 10 p + 21

y^{2} - 9

b - 3.9 = 3.21