What are the solutions to the equation 36x^2-36x+13=0 ?

The solutions to the equation 36x^2-36x+13=0 are x= 1/2+i 1/3 ,x= 1/2-i 1/3

Find the zeros of 36x^2-36x+13=0

The zeros of 36x^2-36x+13=0 are x= 1/2+i 1/3 ,x= 1/2-i 1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

36 x^{2} - 36 x + 13 = 0

x = \frac{1}{2} + i \frac{1}{3}, x = \frac{1}{2} - i \frac{1}{3}

Solution steps

36 x^{2} - 36 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 36 \cdot 13}{2 \cdot 36}

Simplify

(- 36)^{2} - 4 \cdot 36 \cdot 13 : 24 i

x_{1, 2} = \frac{- ( - 36 ) \pm 24 i}{2 \cdot 36}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 24 i}{2 \cdot 36}, x_{2} = \frac{- ( - 36 ) - 24 i}{2 \cdot 36}

x = \frac{- ( - 36 ) + 24 i}{2 \cdot 36} : \frac{1}{2} + i \frac{1}{3}

x = \frac{- ( - 36 ) - 24 i}{2 \cdot 36} : \frac{1}{2} - i \frac{1}{3}

The solutions to the quadratic equation are:

x = \frac{1}{2} + i \frac{1}{3}, x = \frac{1}{2} - i \frac{1}{3}

2 x^{2} - x - 17 = - 5

8.52 = 0 \cdot t + \frac{1}{2} \cdot 9.8 \cdot t^{2}

7 x^{2} - 2 x - 7 = 0

2 x^{2} - 7 + 1 = 0

7 x^{2} - 13 x = 1

What are the solutions to the equation 36x^2-36x+13=0 ?
The solutions to the equation 36x^2-36x+13=0 are x= 1/2+i 1/3 ,x= 1/2-i 1/3
Find the zeros of 36x^2-36x+13=0
The zeros of 36x^2-36x+13=0 are x= 1/2+i 1/3 ,x= 1/2-i 1/3