What are the solutions to the equation x=x^2-18x+32 ?

The solutions to the equation x=x^2-18x+32 are x=(19+sqrt(233))/2 ,x=(19-sqrt(233))/2

Find the zeros of x=x^2-18x+32

The zeros of x=x^2-18x+32 are x=(19+sqrt(233))/2 ,x=(19-sqrt(233))/2

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x = x^{2} - 18 x + 32

x = \frac{19 + 233}{2}, x = \frac{19 - 233}{2}

Decimal Notation

x = 17.13216 \dots, x = 1.86783 \dots

Solution steps

x = x^{2} - 18 x + 32

Switch sides

x^{2} - 18 x + 32 = x

Move

x

to the left side

x^{2} - 19 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 19 ) \pm ( - 19 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

(- 19)^{2} - 4 \cdot 1 \cdot 32 = 233

x_{1, 2} = \frac{- ( - 19 ) \pm 233}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 19 ) + 233}{2 \cdot 1}, x_{2} = \frac{- ( - 19 ) - 233}{2 \cdot 1}

x = \frac{- ( - 19 ) + 233}{2 \cdot 1} : \frac{19 + 233}{2}

x = \frac{- ( - 19 ) - 233}{2 \cdot 1} : \frac{19 - 233}{2}

The solutions to the quadratic equation are:

x = \frac{19 + 233}{2}, x = \frac{19 - 233}{2}

x^{2} + 10 x + 20 = 4

m^{2} + 12 m + 27 = 0

- 2 x^{2} + 10 x = 15

v^{2} - 5 v + 4 = 0

- 6 - 4 a^{2} = - 54

What are the solutions to the equation x=x^2-18x+32 ?
The solutions to the equation x=x^2-18x+32 are x=(19+sqrt(233))/2 ,x=(19-sqrt(233))/2
Find the zeros of x=x^2-18x+32
The zeros of x=x^2-18x+32 are x=(19+sqrt(233))/2 ,x=(19-sqrt(233))/2