What are the solutions to the equation x^2+x-2=e ?

The solutions to the equation x^2+x-2=e are x=(-1+sqrt(4e+9))/2 ,x=(-1-sqrt(4e+9))/2

Find the zeros of x^2+x-2=e

The zeros of x^2+x-2=e are x=(-1+sqrt(4e+9))/2 ,x=(-1-sqrt(4e+9))/2

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x^{2} + x - 2 = e

x = \frac{- 1 + 4 e + 9}{2}, x = \frac{- 1 - 4 e + 9}{2}

Decimal Notation

x = 1.72896 \dots, x = - 2.72896 \dots

Solution steps

x^{2} + x - 2 = e

Move

e

to the left side

x^{2} + x - 2 - e = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 - e )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2 - e) = 4 e + 9

x_{1, 2} = \frac{- 1 \pm 4 e + 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 4 e + 9}{2 \cdot 1}, x_{2} = \frac{- 1 - 4 e + 9}{2 \cdot 1}

x = \frac{- 1 + 4 e + 9}{2 \cdot 1} : \frac{- 1 + 4 e + 9}{2}

x = \frac{- 1 - 4 e + 9}{2 \cdot 1} : \frac{- 1 - 4 e + 9}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 4 e + 9}{2}, x = \frac{- 1 - 4 e + 9}{2}

49 x^{2} - 144 = 0

\frac{x ^{2}}{6} - \frac{11}{6} x + 3 = 0

y^{2} = 4 y - 9

x, x^{2} + (y - 1)^{2} = 4

x, x^{2} + 4 z^{2} - 8 y = 0

What are the solutions to the equation x^2+x-2=e ?
The solutions to the equation x^2+x-2=e are x=(-1+sqrt(4e+9))/2 ,x=(-1-sqrt(4e+9))/2
Find the zeros of x^2+x-2=e
The zeros of x^2+x-2=e are x=(-1+sqrt(4e+9))/2 ,x=(-1-sqrt(4e+9))/2