What are the solutions to the equation 2=3t^2-4 ?

The solutions to the equation 2=3t^2-4 are t=sqrt(2),t=-sqrt(2)

Find the zeros of 2=3t^2-4

The zeros of 2=3t^2-4 are t=sqrt(2),t=-sqrt(2)

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2 = 3 t^{2} - 4

t = 2, t = - 2

Decimal Notation

t = 1.41421 \dots, t = - 1.41421 \dots

Solution steps

2 = 3 t^{2} - 4

Switch sides

3 t^{2} - 4 = 2

Move

4

to the right side

3 t^{2} = 6

Divide both sides by

3

t^{2} = 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 2, t = - 2

d^{2} - 17 d + 16 = 0

32 x^{2} - 5 x - 2 = 0

x^{2} - 15 x + 20 = 0

6 x^{2} + 12 x = 0

x, y (x^{2} + 4) = 10 x

What are the solutions to the equation 2=3t^2-4 ?
The solutions to the equation 2=3t^2-4 are t=sqrt(2),t=-sqrt(2)
Find the zeros of 2=3t^2-4
The zeros of 2=3t^2-4 are t=sqrt(2),t=-sqrt(2)