What are the solutions to the equation (4-x)^2-1=0 ?

The solutions to the equation (4-x)^2-1=0 are x=3,x=5

Find the zeros of (4-x)^2-1=0

The zeros of (4-x)^2-1=0 are x=3,x=5

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(4 - x)^{2} - 1 = 0

x = 3, x = 5

Solution steps

(4 - x)^{2} - 1 = 0

Move

1

to the right side

(4 - x)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

4 - x = 1 : x = 3

Solve

4 - x = - 1 : x = 5

The solutions to the quadratic equation are:

x = 3, x = 5

x, t^{3} = c (t^{2} - x^{2})

b, 6 c^{2} + 6 = c b^{2}

2 x^{2} - 7 = 113

x, 3 x^{2} - 18 x + 5 = 47

4 (3 b + 2)^{2} = 64

What are the solutions to the equation (4-x)^2-1=0 ?
The solutions to the equation (4-x)^2-1=0 are x=3,x=5
Find the zeros of (4-x)^2-1=0
The zeros of (4-x)^2-1=0 are x=3,x=5