What are the solutions to the equation 3v^2-11v-4=0 ?

The solutions to the equation 3v^2-11v-4=0 are v=4,v=-1/3

Find the zeros of 3v^2-11v-4=0

The zeros of 3v^2-11v-4=0 are v=4,v=-1/3

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3 v^{2} - 11 v - 4 = 0

v = 4, v = - \frac{1}{3}

Decimal Notation

v = 4, v = - 0.33333 \dots

Solution steps

3 v^{2} - 11 v - 4 = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 11)^{2} - 4 \cdot 3 (- 4) = 13

v_{1, 2} = \frac{- ( - 11 ) \pm 13}{2 \cdot 3}

Separate the solutions

v_{1} = \frac{- ( - 11 ) + 13}{2 \cdot 3}, v_{2} = \frac{- ( - 11 ) - 13}{2 \cdot 3}

v = \frac{- ( - 11 ) + 13}{2 \cdot 3} : 4

v = \frac{- ( - 11 ) - 13}{2 \cdot 3} : - \frac{1}{3}

The solutions to the quadratic equation are:

v = 4, v = - \frac{1}{3}

t, s = v t + \frac{a t ^{2}}{2}

x^{2} = (33) (63 + 33)

m^{2} + 20 m + 100 = 0

2 a^{2} + 5 a + 3 = 0

x, f = k x^{2} + (x + 1) x + k + 2

What are the solutions to the equation 3v^2-11v-4=0 ?
The solutions to the equation 3v^2-11v-4=0 are v=4,v=-1/3
Find the zeros of 3v^2-11v-4=0
The zeros of 3v^2-11v-4=0 are v=4,v=-1/3