What are the solutions to the equation λ^2+10λ+1=0 ?

The solutions to the equation λ^2+10λ+1=0 are λ=-5+2sqrt(6),λ=-5-2sqrt(6)

Find the zeros of λ^2+10λ+1=0

The zeros of λ^2+10λ+1=0 are λ=-5+2sqrt(6),λ=-5-2sqrt(6)

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λ^{2} + 10 λ + 1 = 0

λ = - 5 + 26, λ = - 5 - 26

Decimal Notation

λ = - 0.10102 \dots, λ = - 9.89897 \dots

Solution steps

λ^{2} + 10 λ + 1 = 0

Solve with the quadratic formula

λ_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 1 = 46

λ_{1, 2} = \frac{- 10 \pm 4 6}{2 \cdot 1}

Separate the solutions

λ_{1} = \frac{- 10 + 4 6}{2 \cdot 1}, λ_{2} = \frac{- 10 - 4 6}{2 \cdot 1}

λ = \frac{- 10 + 4 6}{2 \cdot 1} : - 5 + 26

λ = \frac{- 10 - 4 6}{2 \cdot 1} : - 5 - 26

The solutions to the quadratic equation are:

λ = - 5 + 26, λ = - 5 - 26

5.4 x^{2} + 3 x - 1 = 0

n^{2} - 5 n - 36 = 0

M = x^{2} a + x^{2} b

(2 x)^{2} = 2 x^{2}

x = x^{2} - 3 x + 4

What are the solutions to the equation λ^2+10λ+1=0 ?
The solutions to the equation λ^2+10λ+1=0 are λ=-5+2sqrt(6),λ=-5-2sqrt(6)
Find the zeros of λ^2+10λ+1=0
The zeros of λ^2+10λ+1=0 are λ=-5+2sqrt(6),λ=-5-2sqrt(6)