What are the solutions to the equation 44=-16t^2+64t+80 ?

The solutions to the equation 44=-16t^2+64t+80 are t=-1/2 ,t= 9/2

Find the zeros of 44=-16t^2+64t+80

The zeros of 44=-16t^2+64t+80 are t=-1/2 ,t= 9/2

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44 = - 16 t^{2} + 64 t + 80

t = - \frac{1}{2}, t = \frac{9}{2}

Decimal Notation

t = - 0.5, t = 4.5

Solution steps

44 = - 16 t^{2} + 64 t + 80

Switch sides

- 16 t^{2} + 64 t + 80 = 44

Move

44

to the left side

- 16 t^{2} + 64 t + 36 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 64 \pm 6 4 ^{2} - 4 ( - 16 ) \cdot 36}{2 ( - 16 )}

6 4^{2} - 4 (- 16) \cdot 36 = 80

t_{1, 2} = \frac{- 64 \pm 80}{2 ( - 16 )}

Separate the solutions

t_{1} = \frac{- 64 + 80}{2 ( - 16 )}, t_{2} = \frac{- 64 - 80}{2 ( - 16 )}

t = \frac{- 64 + 80}{2 ( - 16 )} : - \frac{1}{2}

t = \frac{- 64 - 80}{2 ( - 16 )} : \frac{9}{2}

The solutions to the quadratic equation are:

t = - \frac{1}{2}, t = \frac{9}{2}

3 c^{2} - 2 c - 2 = 0

0 = 8 x^{2}

(x + 1)^{2} - 3 = 13

3 x^{2} - 20 x + 31 = 0

(x - 1)^{2} + 3 = 0

What are the solutions to the equation 44=-16t^2+64t+80 ?
The solutions to the equation 44=-16t^2+64t+80 are t=-1/2 ,t= 9/2
Find the zeros of 44=-16t^2+64t+80
The zeros of 44=-16t^2+64t+80 are t=-1/2 ,t= 9/2