What are the solutions to the equation (x+2)^2+(x-1)(x+2)=5x ?

The solutions to the equation (x+2)^2+(x-1)(x+2)=5x are x=i,x=-i

Find the zeros of (x+2)^2+(x-1)(x+2)=5x

The zeros of (x+2)^2+(x-1)(x+2)=5x are x=i,x=-i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x + 2)^{2} + (x - 1) (x + 2) = 5 x

x = i, x = - i

Solution steps

(x + 2)^{2} + (x - 1) (x + 2) = 5 x

Expand

(x + 2)^{2} + (x - 1) (x + 2) : 2 x^{2} + 5 x + 2

2 x^{2} + 5 x + 2 = 5 x

Move

2

to the right side

2 x^{2} + 5 x = 5 x - 2

Move

5 x

to the left side

2 x^{2} = - 2

Divide both sides by

2

x^{2} = - 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 1, x = - - 1

- 1 = i

- - 1 = - i

x = i, x = - i

x^{2} + 6 x = 41

x^{2} - 4 x - 437 = 0

3 x (x + 2) = 2

x^{2} + 3 x - 72 = 0

s^{2} - 2 s

What are the solutions to the equation (x+2)^2+(x-1)(x+2)=5x ?
The solutions to the equation (x+2)^2+(x-1)(x+2)=5x are x=i,x=-i
Find the zeros of (x+2)^2+(x-1)(x+2)=5x
The zeros of (x+2)^2+(x-1)(x+2)=5x are x=i,x=-i