What are the solutions to the equation (-5-x)(-5-x)+36=0 ?

The solutions to the equation (-5-x)(-5-x)+36=0 are x=-6i-5,x=6i-5

Find the zeros of (-5-x)(-5-x)+36=0

The zeros of (-5-x)(-5-x)+36=0 are x=-6i-5,x=6i-5

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(- 5 - x) (- 5 - x) + 36 = 0

x = - 6 i - 5, x = 6 i - 5

Solution steps

(- 5 - x) (- 5 - x) + 36 = 0

Move

36

to the right side

(- 5 - x) (- 5 - x) = - 36

Simplify

(- 5 - x)^{2} = - 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

- 5 - x = - 36 : x = - 6 i - 5

Solve

- 5 - x = - - 36 : x = 6 i - 5

The solutions to the quadratic equation are:

x = - 6 i - 5, x = 6 i - 5

4 (23) x^{2} - 5 x + 4 = 9

4 (x - 1)^{2} + 2 = 38

x^{2} + 6 = 26

3 x^{2} + 8 = 7 x

\frac{x ^{2} - 1}{4} = \frac{x - 1}{3}

What are the solutions to the equation (-5-x)(-5-x)+36=0 ?
The solutions to the equation (-5-x)(-5-x)+36=0 are x=-6i-5,x=6i-5
Find the zeros of (-5-x)(-5-x)+36=0
The zeros of (-5-x)(-5-x)+36=0 are x=-6i-5,x=6i-5