What are the solutions to the equation x^2+1/36 =1 ?

The solutions to the equation x^2+1/36 =1 are x=(sqrt(35))/6 ,x=-(sqrt(35))/6

Find the zeros of x^2+1/36 =1

The zeros of x^2+1/36 =1 are x=(sqrt(35))/6 ,x=-(sqrt(35))/6

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x^{2} + \frac{1}{36} = 1

x = \frac{35}{6}, x = - \frac{35}{6}

Decimal Notation

x = 0.98601 \dots, x = - 0.98601 \dots

Solution steps

x^{2} + \frac{1}{36} = 1

Move

\frac{1}{36}

to the right side

x^{2} = 1 - \frac{1}{36}

Simplify

1 - \frac{1}{36} : \frac{35}{36}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{35}{36}, x = - \frac{35}{36}

\frac{35}{36} = \frac{35}{6}

- \frac{35}{36} = - \frac{35}{6}

x = \frac{35}{6}, x = - \frac{35}{6}

x^{2} + 9 x - 1

x (x + 4) = 3 (x + 4)

- 9 - x^{2} = 0

2 j^{2} - 8 j + 2 = 0

x, z = \frac{x ^{2}}{a ^{2}} + \frac{y ^{2}}{b ^{2}}

What are the solutions to the equation x^2+1/36 =1 ?
The solutions to the equation x^2+1/36 =1 are x=(sqrt(35))/6 ,x=-(sqrt(35))/6
Find the zeros of x^2+1/36 =1
The zeros of x^2+1/36 =1 are x=(sqrt(35))/6 ,x=-(sqrt(35))/6