What are the solutions to the equation 225=x^2+16x ?

The solutions to the equation 225=x^2+16x are x=9,x=-25

Find the zeros of 225=x^2+16x

The zeros of 225=x^2+16x are x=9,x=-25

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225 = x^{2} + 16 x

x = 9, x = - 25

Solution steps

225 = x^{2} + 16 x

Switch sides

x^{2} + 16 x = 225

Move

225

to the left side

x^{2} + 16 x - 225 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 225 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 225) = 34

x_{1, 2} = \frac{- 16 \pm 34}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 34}{2 \cdot 1}, x_{2} = \frac{- 16 - 34}{2 \cdot 1}

x = \frac{- 16 + 34}{2 \cdot 1} : 9

x = \frac{- 16 - 34}{2 \cdot 1} : - 25

The solutions to the quadratic equation are:

x = 9, x = - 25

x^{2} - 4 x + 7 = 0

5 x^{2} - 10 x - 7 = 0

2 x^{2} + x - 24 = 0

3320 = - 2 x^{2} + 180 x - 280

3 m^{2} - (5 m + 1) (2 m - 3) = 3

What are the solutions to the equation 225=x^2+16x ?
The solutions to the equation 225=x^2+16x are x=9,x=-25
Find the zeros of 225=x^2+16x
The zeros of 225=x^2+16x are x=9,x=-25