What are the solutions to the equation 6=24(x+1)^2 ?

The solutions to the equation 6=24(x+1)^2 are x=-1/2 ,x=-3/2

Find the zeros of 6=24(x+1)^2

The zeros of 6=24(x+1)^2 are x=-1/2 ,x=-3/2

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6 = 24 (x + 1)^{2}

x = - \frac{1}{2}, x = - \frac{3}{2}

Decimal Notation

x = - 0.5, x = - 1.5

Solution steps

6 = 24 (x + 1)^{2}

Switch sides

24 (x + 1)^{2} = 6

Divide both sides by

24

(x + 1)^{2} = \frac{1}{4}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = \frac{1}{4} : x = - \frac{1}{2}

Solve

x + 1 = - \frac{1}{4} : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2}, x = - \frac{3}{2}

10 x^{2} + 72 x - 64 = 0

(\frac{- 1}{5} - x)^{2} = 1 - x^{2}

2 m^{2} - 3 m - 5 = 0

(y + 2) (2 y - 5) = 0

8 x^{2} = 9

What are the solutions to the equation 6=24(x+1)^2 ?
The solutions to the equation 6=24(x+1)^2 are x=-1/2 ,x=-3/2
Find the zeros of 6=24(x+1)^2
The zeros of 6=24(x+1)^2 are x=-1/2 ,x=-3/2