What are the solutions to the equation 2x^2-7^2-3=0 ?

The solutions to the equation 2x^2-7^2-3=0 are x=sqrt(26),x=-sqrt(26)

Find the zeros of 2x^2-7^2-3=0

The zeros of 2x^2-7^2-3=0 are x=sqrt(26),x=-sqrt(26)

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2 x^{2} - 7^{2} - 3 = 0

x = 26, x = - 26

Decimal Notation

x = 5.09901 \dots, x = - 5.09901 \dots

Solution steps

2 x^{2} - 7^{2} - 3 = 0

Move

7^{2}

to the right side

2 x^{2} - 3 = 49

Move

3

to the right side

2 x^{2} = 52

Divide both sides by

2

x^{2} = 26

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 26, x = - 26

x^{2} - 10 x + 21

(- \frac{8}{3})^{2} + y^{2} = 1^{2}

x^{2} + 3 x + 21 = 22

a, (a + b + c)^{2} = 225

x^{2} + 2 x = x + 3.75

What are the solutions to the equation 2x^2-7^2-3=0 ?
The solutions to the equation 2x^2-7^2-3=0 are x=sqrt(26),x=-sqrt(26)
Find the zeros of 2x^2-7^2-3=0
The zeros of 2x^2-7^2-3=0 are x=sqrt(26),x=-sqrt(26)